debian-mirror-gitlab/spec/models/board_group_recent_visit_spec.rb
2019-05-18 00:54:41 +05:30

74 lines
2.2 KiB
Ruby

# frozen_string_literal: true
require 'spec_helper'
describe BoardGroupRecentVisit do
let(:user) { create(:user) }
let(:group) { create(:group) }
let(:board) { create(:board, group: group) }
describe 'relationships' do
it { is_expected.to belong_to(:user) }
it { is_expected.to belong_to(:group) }
it { is_expected.to belong_to(:board) }
end
describe 'validations' do
it { is_expected.to validate_presence_of(:user) }
it { is_expected.to validate_presence_of(:group) }
it { is_expected.to validate_presence_of(:board) }
end
describe '#visited' do
it 'creates a visit if one does not exists' do
expect { described_class.visited!(user, board) }.to change(described_class, :count).by(1)
end
shared_examples 'was visited previously' do
let!(:visit) { create :board_group_recent_visit, group: board.group, board: board, user: user, updated_at: 7.days.ago }
it 'updates the timestamp' do
Timecop.freeze do
described_class.visited!(user, board)
expect(described_class.count).to eq 1
expect(described_class.first.updated_at).to be_like_time(Time.zone.now)
end
end
end
it_behaves_like 'was visited previously'
context 'when we try to create a visit that is not unique' do
before do
expect(described_class).to receive(:find_or_create_by).and_raise(ActiveRecord::RecordNotUnique, 'record not unique')
expect(described_class).to receive(:find_or_create_by).and_return(visit)
end
it_behaves_like 'was visited previously'
end
end
describe '#latest' do
def create_visit(time)
create :board_group_recent_visit, group: group, user: user, updated_at: time
end
it 'returns the most recent visited' do
create_visit(7.days.ago)
create_visit(5.days.ago)
recent = create_visit(1.day.ago)
expect(described_class.latest(user, group)).to eq recent
end
it 'returns last 3 visited boards' do
create_visit(7.days.ago)
visit1 = create_visit(3.days.ago)
visit2 = create_visit(2.days.ago)
visit3 = create_visit(5.days.ago)
expect(described_class.latest(user, group, count: 3)).to eq([visit2, visit1, visit3])
end
end
end